Tuesday, October 30th

This is Austin, telling you what we did in class today.

The POD was the prime factorization of 224.

224
/\
2 112
/ /\
2 2 56
/ / /\
2 2 2 28
/ / / /\
2 2 2 4 7
/ / / /\ \
2x 2x2 x 2x2x7 = 2 to the 5th power x 7

2 more problems including prime factorization:

392= 2 to the 3rd power x seven to the 2nd power
-78= -2 x 3 x 13
then we did factoring expressions completly.

10x to the 2nd power = 2 times 5 times x times x times x

-48xy to the 3rd power= (-1) times 8 times 6 times x times y times y times y

-56ba to the 2nd power=(-1) times a times a b times 2 times 2 times 2 times 2 times 3

H.W is read Pg. 159-161. complete Pg. 161 #s 3, 13-39 odd.

we also learned that ato the 0 power is 1

1 example of expanded base 10 form is:

23=2 bundles of 10 and 3 bundles of 1
23=(2 x 10) + (3 x 1)
23=(2 x 10 to the 1st power)+ (3 x 10 to the 0 power)


1=10 to the 0 power 10=10 to the 1st power 100= 10 to the 2nd

346= (10 to the 2nd power x 3)+(10 to the 1st power x 4)+
(10 to the 0 power times 3)

4,003=(10 to the 3rd power x 4)+ (10 to the 0 power x 3)


computers use the base 2 form(bianary code).

1=on 0=off

Example:
21=10101

I choose Gabriel to be the next scribe.