Tuesday, November 6, 2007

Hey guys its Gabriel with today’s lesson and POD

Treating each letter as a variable and treating each space as a multiplication symbol, write the following expression in expediential form:
Good golly miss Molly
The answer was: g2o4dl4y2is2m2 there were 2 G’s, 4 O’s, 1 D, 4 L’s, 2 Y’s, 1 I, 2 S’s, and 2 M’s.

Mr. A. asked if there were any H.W. questions. Lilly had one, it was:
And it was wrong. Sirus and Karol tried it and both got it wrong. You know what that means…. this problem is impossible (just kidding). Then Margo did it and did it right. The answer was
Mr. A. gave an example: it actually was because if the nominator has no value you put a 1 in it. By the way a nominator is the top part of a fraction.

Then Mr. A. asked us to do some problems.

1) A. Write 8 as a product of factors of 2. = 2x2x2
B. Write 8 as a product of powers of 2. = 21x21x21
C. Write 8 as a single power of 2. = 23

2) A. Write 16 as a product of factors of 14. =4x4
B. Write 16 as a product of factors of 22. =22x22
C. Write 16 as a single of a power of 2. =22

3) A. Write 27 as a product of factors of 3. = 3x3x3
B. Write 27 as the product of 2 with different powers of 3. =31x32
C. Write 27 as a single of powers of 3. = 33

4) A. Write 81 as a product of factors of 3. = 3x3x3x3
B. Write 81 as a product of factors of . = 31x32
C. Write 81 as a single of a power of 3. = 34

Since all of that was sort of difficult to read Mr. A. made a table which s the following:
8= 2x2x2 21x21x21 23
16= 4x4 22x22 24
27= 3x3x3 32x31 33
81= 3x3x3x3 31x32 34
amxan=? am-n

PRODUCT OF POWERS: am x an=am-n

If expressions with the same base are multiplied, then keep the base and add the powers.

Then we had to do some more math problems that Mr. A. gave us.

1) 23 x 25 = 23+5 = 28

2) 63x 63=66

3) (-9)2(-9)2= 94

4) 10t2 x 4t10 = 40t12

5) (4f8) (5f6) = 20f14

6) (8c2) (9c) = 72c3

None of the problems will be on the test on Wednesday. The key to these problems is you multiply the bases and add the exponents and leave your variable if you have one. Number 6 might seem a little confusing if you weren’t at class today. If there s no exponent, just pretend that there is a #1 in the empty space.

H.W. read pgs. 175-176 pg.178 13-23 odd, and 47, 57, 61.

REMINDER: The test on Wednesday consists of the following:

1) exponents
2) prime and composite numbers
3) divisibility rules
4) GCF of algebraic expressions
5) Simplifying fractions
6) And last but not least, writing in base 2 form(everyone’s favorite)


I nominate Lilly to be the next scribe!!!!!!!!!!!

Monday, November 5, 2007

Sirus Needs Help

Hi guys. . . As the title says, it's me, Sirus. Actually, I didn't write down the homework, and Gaberiel is taking forever, so can anyone tell me what the homework is? Thanks in advance. . .

Thursday, November 1, 2007

what we did in pre-algebra nov. 1

HELLO,
Today in per-algebra class we did the following POD:

POD 11/1
An old lady wants to give her grandchildren her tresure. She has 135 gold coins and 105 esmeralds. She wants to give all them away.
a) what is the maximum number of grand children that can recieve an identical amount of esmeralds and coins?
b) how many esmeralds will each children get?
so the answer to the pod is the followingthe old lady can give it to 15 of her grandchildren for letter a, you can find this if you do a factor tree. and for leeter b she can give 7 esmeralds because if you divide15 into 105 you will get 7-

If you can try to find the GCF. We work on finding the GCF:
a. 24 and 60 and 18
b. 16x and 4x
c. 20xyy and 8xxy

We work on factoring Algecraic Expressions
5x + 45 = 5(x + 9)
- First to solve this problem you find the Gcf of 5 and 45.
The GCF= 5
-Second divide 5x and 45 by the GCF.
5x: 5= x and 45: 5= 9
-Then write the Gcf in the front of the parethesis
5( )
-Then put the solution of the division of the Gcf and the numerator
5( x + 9)
-This is the algebraic expression of 5x + 45=

Try to solve the following:
36 - 4x=

THEIR IS NO HOMEWORK FOR TONIGHT!!!!!!!!!!!!!!!!!!!!!!!!!!!!

THE NEW SCRIBE IS MARCO