Hey, It's the Halloween scribe post. ooooooooh.

Hey guys, it's me, Sirus again. I'm only doing this because Gaberiel isn't gonna be at his home until like 2:00 AM, so yeah. It's me.

Anyway, our POD.

Our POD was to write 11101 in base 10.
OK, so the way to figure this out follows.
To solve base 2, you go from right to left. So the last 1, in 11101, stands for 2 to the zeroeth, so 1. The zero is a place holder, and the 3rd digit, another 1 stands for 2 to the second, or 4. If you continue to do this, you will end up with 16+8+4+0+1, which equals 29. Since 29 is in base 10, 11101 in base 10 is 29.

After this, we practiced with some more binary, or base 2 numbers.

For example, 42 in base 2 is 101001.
40= 101000
53= 110101
55= 110111

Try finding 82 in base 2.

Next, we practiced turning base 2's into base 10's, with problems that we made up.
Gaberiels was 11110110, which turns into: 128+64+32+16+0+4+2+0, or 244. At least, that's what Gabe has on his paper of notes.

The last thing we learned was how to find the GCF, or Greatest Common Factor using factor trees. The steps were thus.

1) Find prime factors of each number.
2) Write the prime factors of each, writing out the exponents.
3) Circle all of the common factors.
4) Choose one row/set of the circled numbers.
5) Multiply the numbers.

One of our examples was 18 and 44.
The prime factorization of the two were:



Don't make fun of my picture, my wordperfect was on the fritz, so I just used paint.
Next, circle one 2 from each, as those are the only common factors. Next, multiply them.
You will find that the GCF is 2.

Another was 220 and 56, which if you will look:


The Homework was to read pages 164-166, and to do problems 17-29 (?) odd. Don't quote me on that. It might have been 17-31. For some reason, Gaberiel didn't write that down, but I'm not blaming him. Anyway, Mr. A said that he probably wouldn't collect the homework.

I pick (drum roll please) Karol to be the next scribe.